(b) the probability that this adult in- deed has the disease will be 0.0286
(c) The probability that this adult ac- actually has the disease after negative test result will be: 0.0007
(a) The tree diagram containing the probabilities is attached below.
(b) The probability that this adult in- deed has the disease will be:
[tex]$P(\text { d } \mid \text { positive })=\frac{0.002 \times 0.968}{0.002 \times 0.968+0.998 \times 0.066}=0.0286$[/tex]
(c) The probability that this adult ac- actually has the disease after negative test result will be
[tex]$ \begin{aligned}P(d | \text { negative })= & \frac{0.002 \times 0.032}{0.002 \times 0.032+0.998 \times 0.934} \\= & 0.00007\end{aligned}$[/tex]
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