A simple random population that is normally distributed then the 95% confidence interval is (104.02, 111.98)
In mathematics and statistics, the mean refers to the average of a set of values. The mean can be computed in a number of ways, including the simple arithmetic mean (add up the numbers and divide the total by the number of observations), the geometric mean, and the harmonic mean.
Given that,
Sample Mean = 108,
Standard deviation = 10,
Sample n = 25,
Degree of freedom = n-1
n - 1 = 25 - 1
n - 1 = 24.
t-value corresponding to 24 degrees of freedom and 95% confidence level is 1.990
Confidence Interval = Mean + or - Error margin
Error margin (E) = (t×sd)/√n
E = (1.990×10)/√25
E = 19.9/5
E = 3.98
Lower bound = mean - E
= 108 - 3.98
= 104.02
Upper bound = mean + E
= 108 + 3.98
= 111.98
Therefore,
A simple random population that is normally distributed then the 95% confidence interval is (104.02, 111.98)
To learn more about Confidence interval visit :
brainly.com/question/13646086
#SPJ4
