Question

if member bd is an a992 steel rod of radius 2.4 in ., determine the maximum load p that can be supported by the truss without causing the member to buckle.

Answer 1

The declaration claims that the truss can support 77.689 Kips without enabling the member to collapse.

What purposes do truss serve?

Trusses are typically utilized in bridges, towers, cranes, walkways, and roof structures for big span buildings. They can support heavier loads and utilise cross-sections more effectively.

Briefing:

∑MG = 0

(48)*Ay - 32*P-16*P=0

Ay = P

Considers joint A

∑fy = 0

Ay - $F_{AB}$ Sin∅ = 0

Ay - $F_{AB}$ Sin (36.87°) = 0

P - $F_{AB}$ Sin (36.87°) = 0

$F_{AB}$ = P-/0-6

Given:

r = 2.4 in⁴

and moment of inertia;

I = r/64*d⁴

 = r/64(2*2.4)⁴

I = 26.05 inch

From Euler's formula:

$P_{cr}$ = r²EI/(k2)²

$F_{AB}$ = r²EI/(k$L_{AB}$)²

$\frac{P}{0.6}=\frac{r^2 \cdot\left(29 \times 10^3 \mathrm{kes} 1\right) \times\left(26.0576^{\circ} \mathrm{in}^4\right)}{(1 \times 20 \times 12)^2}$

P = (129.482)*0.6

P = 77.689 Kips

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