The pressure block a applies to the loop will be:
Pressure = (mg)/(πdiameter x h)
To find the pressure that block A applies to the loop, we need to consider the forces acting on block A as it goes around the loop. When the block is at the top of the loop, the only force acting on it is the normal force from the loop. The normal force is perpendicular to the surface of the loop and has a magnitude equal to the weight of the block, mg.
The pressure is given by the force per unit area, so we need to divide the normal force by the area of the loop in contact with the block. The area of the loop in contact with the block is equal to the circumference of the loop times the width of the block.
The circumference of the loop is equal to:
2π(diameter/2) = π x diameter
And the width of the block is equal to h.
Therefore, the pressure applied by block A to the loop at the top of the loop is given by:
Pressure = (normal force)/(area)
P = (mg)/(pidiameterh)
Substituting in the values for the mass and height of the block, we get:
Pressure = (mg)/(πdiameter*h)
Learn more about Pressure, here https://brainly.com/question/12971272
#SPJ4
