Respuesta :
the horizontal distance of the projectile before striking the ground 20m
Calculation :
Given data:
- h=20 m is the height of the cliff
- ux=10 m/s is the initial horizontal speed of the projectile
- d is the distance covered by the projectile in the horizontal direction
- t is the time interval
- uy=0 m/s is the vertical component of the launch speed of the projectile in the vertical direction
Since there is no initial vertical speed of the projectile; therefore, the time of fall is equal to the time required by the projectile to hit the ground.
s=uyt+[tex]\frac{1}{2}[/tex]at²
⟹h=0+[tex]\frac{1}{2}[/tex]gt²
⟹t²=2h/g
⟹t=[tex]\sqrt{\frac{2*20m}{9.81 m/s^{2} } }[/tex]
⟹t=2.02 s
The horizontal speed of the projectile does not change during motion. Hence, the horizontal distance covered by the projectile between time "
t" is:
Speed=distance/time
⟹d=[tex]u_{x}[/tex]t
⟹d=10 m/s×2.02 s
⟹d=20.2 m
⟹d=20 m
A projectile is an object that is propelled by the application of an external force and moves freely under the influence of gravity and air resistance. All objects that move in space are projectiles, but they are commonly found in warfare and sports (e.g., baseballs thrown, soccer balls kicked, bullets fired, Darts, rocks thrown by catapults are ejected).
A kinetic energy weapon (also known as a kinetic weapon, kinetic energy warhead, kinetic warhead, kinetic projectile, or kinetic killing vehicle) is a weapon that relies solely on the kinetic energy of the projectile, not explosives or other types of payloads. .
The term hit-to-kill or kinetic kill is also used in military aerospace to describe kinetic energy weapons. Used primarily in the anti-ballistic missile (ABM) and anti-satellite weapon (ASAT) sectors, but some modern anti-aircraft missiles are also hit-to-kill. Hit-to-Kill systems are part of a broader class of dynamic projectiles, a class widely used in the anti-tank space.
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