Question

A student applies a force F at an angle of θ below the horizontal to a 50 kg desk, which causes the desk to move across the room at a constant speed.
Angle θ= 20 Degrees
Force= 200 N
Draw and label an appropriate force vector diagram for the desk.
What is the weight of the desk?
What is the magnitude of the normal force acting on the desk?
What is the magnitude of the friction force acting on the desk?

Answer 1

The magnitude of the weight, normal and friction forces are 490N, 455N and 16.66N respectively.

The force applied by the student at the angle of 20 degrees has a magnitude of 200N.

The desk is moving across the room with a constant speed.

The mass of the desk is Kg.

The weight of the desk is given by,

W = Mg

Where,

g is acceleration due to gravity.

Putting values,

W = 50 x 9.8

W = 490N.

The magnitude of the normal force is given by,

N = WcosA

Where,

A is the angle with x-axis.

Putting values,

N = 490 x cos(20)

N = 455N.

The magnitude of the Friction force is given by,

F = W x sin(20)

F = 490 x 0.34

F = 16.66N.

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