A 1750-N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and weighing 0.290 N. The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached. If you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling? Which pulse arrives first? (Ignore the effect of the weight of the wires on the tension in the wires.)

The weight of the irregular beam is given to be one 50 Newton's and it is hanging horizontally by its end from the ceiling are test by two strings of 1.2 metre and 0.290 New mass each.

The strings are plucked at the same time.

The time of the the object taken to reach the bottom is given by,

T = √(2H/g)

As we can see from the above relation that that time taken by the object to reach the bottom is not dependent on the mass of the object.

So, when the springs are pluck.

Both the ends of the beam will reach the ground at the same time and there will be no time delay between the arrival of the two pulses at the ceiling.

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