Calculate the margin of error of a confidence interval for the difference between two population means using the given information. Round your answer to six decimal places.σ1=5.94σ1=5.94, n1=98n1=98, σ2=2.87σ2=2.87, n2=79n2=79, α=0.05

In statistics, the term margin of error is calculated by multiplying a critical factor with the population standard deviation and then the result is divided by the square root of the number of observations in the sample.

Margin of Error = Z * ơ / √n.

Here we have to calculate the margin of error of a confidence interval for the difference between two population means using the given information.

While we looking into the given question we have given the values,

σ1=5.94

n1=98

σ2=2.87

n2=79

α=0.05

Here we have to calculate the margin of error for the value 1, n1, and α

First, find the critical value: zα2=1.9599

Next, find the standard error of the mean which is

SE = 297√2/√700

Finally, the margin of error is 1.1760

Similarly, the value for the nest set of values is,

First, find the critical value: zα2=1.9599

Next, find the standard error of the mean: SE = 287√79/√7900

Finally, the margin of error is ME = 0.6328

Then the difference between these population is

=> 1.1760 - 0.6328

=> 0.5432

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