Initial bar power is U0; final bar power is U0 divided by 2; bar Energy in motion K = U0 / 2. The height of these two bars is halved from that of the first bar.
Let's talk about the answer to the problem to determine which graph is accurate.
mechanical energy at first
Em0=U0=m g H
The midpoint's mechanical energy
Em₂ = K + U₂
Mechanical energy is preserved since there is no friction.
U0 = K + U2 Em0 = Em2
K = U₀ - U₂
K = m g (H - y₂)
shows that the equation for position 2 is y2 = H / 2 K = m g (H -H / 2).
K = 1/2 mg H K = 1/2 Uo
Consequently, the graph has to be
Beginning: bar power U0
Bar power U = U0 / 2 bar is the conclusion. Energy in motion K = U0 / 2
The height of these two bars is equal to that of the first bar.
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