an object initially at rest falls from a height h until it reaches the ground. two of the following energy bar charts represent the kinetic energy k and gravitational potential energy ug of the object-earth system at two positions. the first position is when the object is initially released, and the second position is when the object is halfway between its release point and the ground. which two charts could represent the mechanical energy of the object-earth system? select two answers.

Respuesta :

Initial bar power is U0; final bar power is U0 divided by 2; bar Energy in motion K = U0 / 2. The height of these two bars is halved from that of the first bar.

Let's talk about the answer to the problem to determine which graph is accurate.

mechanical energy at first

Em0=U0=m g H

The midpoint's mechanical energy

Em₂ = K + U₂

Mechanical energy is preserved since there is no friction.

U0 = K + U2 Em0 = Em2

K = U₀ - U₂

K = m g (H - y₂)

shows that the equation for position 2 is y2 = H / 2 K = m g (H -H / 2).

K = 1/2 mg H K = 1/2 Uo

Consequently, the graph has to be

Beginning: bar power U0

Bar power U = U0 / 2 bar is the conclusion. Energy in motion K = U0 / 2

The height of these two bars is equal to that of the first bar.

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