Question

A rigid 11.7 L sealed vessel containing 3.3 mol O2(g), 1.6 mol CH4(g) and 2.3 mol of He(g)
has an internal temperature of 78oC.
a. Calculate the partial pressure of each gas.b. What is the total pressure in the vessel?
c. Find the mole fraction of each gas in the vessel.d. A lab technician ignites the mist in the flask and the methane gas combusts in oxygen
to form carbon dioxide and water. Find the mole fraction of each gas in the mixture
after the reaction.

Answer 1

a) Partial pressures is Po2 = 8.13 atm,Pch4=3.94atm,Phe = 5.6 atm,B) Total pressure= 17.73 atm, C) mole fraction are Хо2 =0.46, xch4=0.22, xhe=0.32.

mole fraction are Хo2 =3.3/3.3+ 16 + 2.3,Хо2 =0.46, xch4=0.22, xhe=0.32. Xo2 = no2/no2 + nch4 + nhe, total pressure = 8.13+3.94+5.6=17.73 atm. The pressure applied by a solitary gas in a combination is did refer to as its partial pressure. Presuming we get a combination of ideal gas law, we could use ideal gas equation to resolve issues involving gases inside a mixture. Partial Pressure can be defined as if a canning jar filled with far more than one gas, evey gas enforces pressure. The pressure of any gas enclosed within in the container is regarded to as its partial pressure. The number of molecules of a special component in a mix divided by the total amount of moles in the given medium is symbolised by the mole fraction. It's a means of expressing a solution's concentration.

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