The acceleration of gravity of the satellite, as compared to the acceleration of gravity on the surface of Mars is (D) 1/16.
The term Acceleration defined as the gravity at the surface of Mars is given by the formula
Gₙ = GM/R²
where
M refers mass of Mars
R refers radius of Mars
Here we need to find if we take a point which is at height 3 times the radius of Mars from its surface.
While we take the height 3 times the radius of Mars from its surface.
The it can be written as,
=> Gₙ = GM/(3R + R)²
When we expand it then we get.
=> Gₙ = GM/16R²
Therefore, the resulting gravity on the surface of the mars is 1/16.
So, the option (D) is correct.
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