Respuesta :

Answer:

[tex]\textsf{C.} \quad d=\dfrac{2x+3}{p}-z[/tex]

Step-by-step explanation:

Given equation:

[tex]p(d+z)=2x+3[/tex]

Divide both sides by p:

[tex]\implies \dfrac{p(d+z)}{p}=\dfrac{2x+3}{p}[/tex]

[tex]\implies d+z=\dfrac{2x+3}{p}[/tex]

Subtract z from both sides:

[tex]\implies d+z-z=\dfrac{2x+3}{p}-z[/tex]

[tex]\implies d=\dfrac{2x+3}{p}-z[/tex]

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