Respuesta :
We want to have the variable h on one side of the equation and everything else on another side. A good place to start is to divide both sides by 1/2. That way we get rid of that nasty fraction.
A / 1/2 = 1/2bh / 1/2
Now on the left the 1/2 cancels out.
A / 1/2 = bh
And when a number is divided a fraction it's the same multiplying it inverted.
Now it is A(2/1) = bh
Now for the final step, divide both sides by b.
A(2) / b = bh/b
On the left b cancels out and we are left with the final product.
A(2) / b = h or h = A(2) / b
A / 1/2 = 1/2bh / 1/2
Now on the left the 1/2 cancels out.
A / 1/2 = bh
And when a number is divided a fraction it's the same multiplying it inverted.
Now it is A(2/1) = bh
Now for the final step, divide both sides by b.
A(2) / b = bh/b
On the left b cancels out and we are left with the final product.
A(2) / b = h or h = A(2) / b
The formula for the indicated variable is h = 2A ÷ b
Further explanation
Solving linear equation mean calculating the unknown variable from the equation.
Let the linear equation : y = mx + c
If we draw the above equation on Cartesian Coordinates , it will be a straight line with :
m → gradient of the line
( 0 , c ) → y - intercept
Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :
[tex]\large {m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :
[tex]y - y_1 = m ( x - x_1 )[/tex]
Let us tackle the problem.
GIven :
[tex]A = \frac{1}{2} ~ b ~ h[/tex]
[tex]A \times 2 = \frac{1}{2} ~ b ~ h \times 2[/tex] → multiply 2 for both sides
[tex]A \times 2 = b ~ h[/tex]
[tex]b ~ h = A \times 2[/tex] → switch sides to make reading easier
[tex]b ~ h \div b = A \times 2 \div b[/tex] → divide by b
[tex]h = A \times 2 \div b[/tex]
[tex]\large {\boxed {h = \frac{2A}{b}} }[/tex]
Learn more
- Infinite Number of Solutions : https://brainly.com/question/5450548
- System of Equations : https://brainly.com/question/1995493
- System of Linear equations : https://brainly.com/question/3291576
Answer details
Grade: High School
Subject: Mathematics
Chapter: Linear Equations
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point
