Question

The entrance to the louvre museum in paris, france, is a square pyramid. the side length of the base is 116 feet, and the height of one of the triangular faces is 91.7 feet. find the surface area of the four triangular faces of the entrance to the louvre museum.

Answer 1

the surface area of the four triangular faces can be solve by just using the formula for the area of a triangle, since we are given the height of the one of the triangular faces which is 91.7 ft. and the base is 116 ft

the total surface area = 4 (0.5bh)
we multiply i by 4 because there 4 faces 
b is the base
h is the height
A = 4(0.5) ( 116 ft) ( 91.7 ft)
A = 21274.4 sq ft is the surface area of the four triangular faces

Answer 2

The area of the four triangular sides of the pyramid is 21,274.4 ft².

What is the area of a Triangle?

The area of a triangle is half the product of the base of the triangle and the height of the triangle.

$\rm{ Area \triangle = \dfrac{1}{2} \times base \times height$

Given to us

• the height of the triangle face = 91.7 feet
• the length of the base of the pyramid = 116 feet

Area of a Triangular Face

$\rm{ Area \triangle = \dfrac{1}{2} \times base\ length \times height\ of\ the\ triangular\ face$

Substituting the value

$\rm{ Area \triangle = \dfrac{1}{2} \times 119\times 91.7$

           $=5,318.6\ ft^2$

Area of the four triangular sides of the pyramid

Area of the four triangular sides

                                      = 4 x Area of a Triangular Face

                                      = 4 x5,318.6

                                      = 21,274.4 ft²

Hence, the area of the four triangular sides of the pyramid is 21,274.4 ft².

Learn more about a triangle:

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