Question

in simplest a+bi form, the roots of the equations x^2=6x-10 are?

Answer 1

I hope this helps you



x^2-6x+9= -1


(x-3)^2= -1


(x-3)^2=i^2


x-3=i


x=3+i


x=3-i


or we can find disctirminant



x^2-6x+10=0



a=1



b= -6



c=10



disctirminant=b^2-4ac



disctirminant=(-6)^2-4.1.10



disctirminant=36-40


disctirminant= -4


i^2= -1



x1,2= -b (+,-) square root of disctirminant /2a



x1= -(-6)+square root of -4/2.1



x1=6+2i/2=3+i


x2= -(-6)-square root of -4/2.1



x2=6-2i/2=3-i