The score that Avery must get on Exam B is given as follows:
470.
The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.
For exam A, the mean and the standard deviation are given as follows:
[tex]\mu = 350, \sigma = 20[/tex]
She scored 310, hence the z-score of her grade is given as follows:
Z = (310 - 350)/20
Z = -2.
For exam B, the mean and the standard deviation are given as follows:
[tex]\mu = 550, \sigma = 40[/tex]
To do as well as on exam A, she needs a z-score of -2, hence the grade X is obtained as follows:
-2 = (X - 550)/40
X - 550 = -80
X = 470.
More can be learned about the normal distribution at https://brainly.com/question/25800303
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