if boron, b, is diffused into a thick slice of si with no previous b in it at a temperature of 1100°c for 5 h, what is the depth below the surface at which the concentration is 1017 atoms/cm3 if the surface concentration is 1018 atoms/cm3? d

Respuesta :

The depth below the surface at which the concentration is 1017 atoms/cm³ if the surface concentration is 1018 atoms/cm³ is 0.32 cm.

The expression is given as :

( Cs - Cx ) / ( Cs - Co ) = erf ( x / 2 √D × t )

where, Cs = concentration of surface = 1018 atoms/cm³

Cx = concentration at depth = 1017 atoms/cm³

Co - concentration of solute in solid

erf = error function

( Cs - Cx ) / ( Cs - Co ) = (1018 - 1017) / 1018

                                    = 0.00098

0.00098 =  erf ( x / 2 √D × t )

0.000868 = x / 2 √ 2 × 10⁻² × 5 (3600)

x = 0.32 cm

The depth is 0.32 cm

To learn more about depth here

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