3. consider the following reaction: c2h2 (g) + h2 (g) ↔ c2h4 (g) what is the value of the equilibrium constant at 298 k?

Respuesta :

The value of the equilibrium constant at 298 k is 0.9448.

the reaction is given as :

C₂H₂  +   H₂   ----->   C₂H₄

The ΔG°f at 298 K for C₂H₂ = 209 kJ/mol

the ΔG°f at 298 K for  H₂ = 0

the  ΔG°f at 298 K for  C₂H₄ = 68.4 kJ/mol

ΔG°f  = 209 - 68.4 + 0

ΔG°f  = 140.6 kJ/mol

the equilibrium constant expression is given as :

ΔG = ΔG°f + RT lnk

for equilibrium : ΔG = 0

k = e^-ΔG°f /  RT

k = e^( -140.6 / 8.314 × 298 )

k= e^(-0.0567)

k = 0.9448

Thus, the value of equilibrium constant k is 0.9448.

To learn more about equilibrium constant here

https://brainly.com/question/13423433

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