The two bonds are most similar in polarity are Pb - O and Na - O.
let us find out the electronegativity difference between the each pair :
a) C - F = 3.98 - 2.55 = 1.43
N -F = 3.98 - 3.04 = 0.94
b) Pb - O = 3.44 - 2.33 = 1.11
Na - O = 2.33 - 0.93 = 1.4
c) H - F = 3.98 - 2.2 = 1.78
Cl - F = 3.98 - 3.16 = 0.82
d) K - Cl = 3.16 - 0.82 = 2.34
Ni - Cl = 3.16 - 1.91 = 1.25
e) Mg - F = 3.98 - 1.31 = 2.67
I - Br = 2.96 - 2.66 = 0.3
To learn more about polarity here
https://brainly.com/question/19524739
#SPJ4