a. test statistic = 1.35
p-value = 0.198439
b. Support the null hypothesis.
So you have the hypothesis:
H₀:μ=4
H₁:μ≠4
with the sample information you calculate the statistic using the t-distribution with 14 (n-1) degrees of freedom:
t=x[bar] - μ ⇒ t= 4.8 - 4 = 0.8 = 1.347≅ 1.35
s/√n 2.3/√15 0.59
The p-value is defined as the probability corresponding to the calculated statistic (or of obtaining a value as extreme as the value of the statistic) if possible under the null hypothesis.
p-value: 0.198439
b.
Since the calculated p-value is greater than the significance level, you don't reject the null hypothesis.
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