Use a Riemann sum with 4 rectangles of equal width to approximate the area between y=3x^(2)+1 and the x-axis on the interval -1,5. Use the left -hand endpoint of each subinterval.

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The approximate area between y=3x^(2)+1 and the x-axis on the interval -1 to 5 is 136.6875.

We can approximate the area between y=3x^(2)+1 and the x-axis on the interval -1 to 5 using a Riemann sum with 4 rectangles of equal width. The left-hand endpoint of each subinterval will be used.

The width of each rectangle is the length of the interval (5-(-1)) divided by the number of rectangles (4). Therefore, the width of each rectangle is

(5-(-1))/4 = 6/4 = 1.5.

Since we are using the left-hand endpoint of each subinterval, the x-values of the left-hand endpoints of the rectangles are

-1, -1+1.5

-1+1.5+1.5

-1+1.5+1.5+1.5 = -1+4.5=3.5

The height of each rectangle is determined by the value of y at the corresponding x-value.

Therefore, the heights of the rectangles are

3(-1)^2+1=2

3(-1+1.5)^2+1=7.125

3(3.5)^2+1=35.125

3(3.5+1.5)^2+1=46.875

The area of each rectangle is the product of its width and height, so the areas of the rectangles are

2*1.5=3

7.125*1.5=10.6875

35.125*1.5=52.6875

46.875*1.5=70.3125.

Therefore, the approximate area between y=3x^(2)+1 and the x-axis on the interval -1 to 5 is 136.6875.

Learn more about Riemann sum here:

https://brainly.com/question/28969415

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