Question

An 1300-turn coil of wire that is 2.0 cm in diameter is in a magnetic field that drops from 0.15 T to 0 T in 11 ms. The axis of the coil is parallel to the field. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. Part A What is the emf of the coil?

Answer 1

The magnitude of the induced EMF in the coil is 5.56V.

The number of turn in the coil is 1300 and the diameter of the coil is 2.0 cm. The magnetic flux changes from 0.15T to 0 T in 11ms.

The induced EMF in the coil can be found as,

E = nAΔB/t

Where,

n is the number of turn in the coil,

A is the area,

B is the magnetic field and t is the time,

Putting values,

E = 1300 x π(0.01)² x 0.15/11 x 10⁻³

Solving further,

E = 5.56 V.

So, the EMF induced in the coil is 5.56 V.

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