The angular velocity of the pendulum at the bottom is 2.82 rad/s.
The length of the pendulum rod is 1.5ma nd the radius of the pendulum is 0.8m. The mass of the pendulum bob is 14kg and the mass of the rod is 3 kg.
When the pendulum is dropped,
Rotational kinetic energy = Potential energy
Iw²/2 = Mg(L+R) + mgL
Where,
L is the length of the rod and the R is the radius of the bob and I is the moment of inertia of the system while W is the angular speed,
[mL²/3 + MR² + M(L+R)²]W²/2 = Mg(L+R) + mgL
Now, solving the above complex equation,
W = 2.82 rad/s.
So, the angular speed of the pendulum is 2.82 rad/s.
To know more about angular speed, visit,
https://brainly.com/question/25279049
#SPJ4
Complete question- The pendulum consists of a 14 kg uniform disk and a 3 kg uniform slender rod. It is released from rest in the position shown. Suppose that L = 1.5 m. Determine the angular velocity, measured clockwise, when it rotates clockwise 90 degrees.
