Respuesta :
The five correct steps on oxidative decarboxylation of pyruvate are:
- Pyruvate reacts with TPP and is decarboxylated, forming hydroxyethyl-TPP.
- The lipoamide arm of E2 moves to the active site of E1, enabling the transfer of the acetyl group to the lipoamide.
- The acetyl lipoamide arm of E2 moves to the active site of E2, where the acetyl group is transferred to CoA, forming acetyl-CoA and the reduced form of lipoamide.
- The lipoamide arm move to the active site of E3, where the reduced lipoamide is oxidized by FAD, forming the active lipoamide and FADH2.
- FADH2 is reoxidized to FAD, reducing NAD+ to NADH.
These steps are correct in the process of oxidative decarboxylation of pyruvate, because they describe the complete process of pyruvate decarboxylation, from the initial conversion of pyruvate to hydroxyethyl-TPP, to the transfer of the acetyl group to CoA, to the reoxidation of FADH2. This sequence of steps ensures that the energy from the oxidation of pyruvate is captured and stored as energy-rich molecules, such as NADH and acetyl-CoA.
What does the oxidative decarboxylation process consist of?
Is a type of metabolic reaction in which a carboxylic acid is converted into an aldehyde, alcohol, or ketone by the addition of an oxidizing agent, such as oxygen or a metal compound.
This reaction involves the removal of a carboxyl group (COOH) and the addition of an oxygen atom (O). The resulting product contains either an aldehyde, alcohol, or ketone group, depending on the starting material.
Learn more about the oxidative decarboxylation process:
https://brainly.com/question/14143897
#SPJ4