However, Bellman-temporal Ford's complexity is O(VE), which is higher than Dijkstra's. where there are many vertices (V) and many edges (E).
V = n, E = O for a whole network with n vertices (n2). Thus, the entire time complexity is O. (n3). If the edges in your graph have weights, it is considered to be a weighted graph; otherwise, it is said to be an unweighted graph. Each edge has a weight, which is a numerical value. Dijkstra's technique doesn't work for unweighted graphs, as I discovered from the comments. I take it that by "unweighted graphs" you mean those with a fixed weight per edge, like 1. Otherwise, it's ambiguous what the term "shortest path" might signify.
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