Design an algorithm, as efficient as possible, that outputs all the squares that can reach the bottom right square (again, assume that one can only go froma square to an adjacent square with a lower altitude). In particular, the algorithm should output a list of squares that if you start there, it is possible to reach the bottom right square.-Please provide runtime of algorithm-you must specify the graph that you con-struct from a non-graph input (i.e., which are the vertices, edge? Weighted or unweighted? Directed or undirected? If directed, you must specify the edges’ directions).

Respuesta :

However, Bellman-temporal Ford's complexity is O(VE), which is higher than Dijkstra's. where there are many vertices (V) and many edges (E).

V = n, E = O for a whole network with n vertices (n2). Thus, the entire time complexity is O. (n3). If the edges in your graph have weights, it is considered to be a weighted graph; otherwise, it is said to be an unweighted graph. Each edge has a weight, which is a numerical value. Dijkstra's technique doesn't work for unweighted graphs, as I discovered from the comments. I take it that by "unweighted graphs" you mean those with a fixed weight per edge, like 1. Otherwise, it's ambiguous what the term "shortest path" might signify.

Learn more about network here-

https://brainly.com/question/13992507

#SPJ4

RELAXING NOICE
Relax