you are on a rollercoaster and begin to approach a circular loop at 24.5 m/s. the diameter of the loop is 19.7 m. a) find your speed at the top of the loop, assuming the track is frictionless

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Speed at the top of the loop, assuming the track is frictionless

vf = 14.61 m/sec

v = 24.5 m/sec

r = 19.7 m

At the top of the loop using energy conservation

KEb + UEb = KEt + UEt

UEb = 0

UEt = m*g*d

0.5*m*vi^2 + 0 = 0.5*m*vf^2 + m*g*d

vf = sqrt (vi^2 - 2*g*d)

vf = sqrt (24.5^2 - 2*9.81*19.7)

vf = 14.61 m/sec

It is important to note that an object's speed, also known as "v," is a scalar quantity that measures how much an object's position changes over time or how much it changes per unit of time. An object's average speed during a period of time is calculated by dividing its distance travelled by the length of the interval; the instantaneous speed is the maximum possible speed as the interval's duration gets closer to zero. Velocity and speed are different concepts.

The metre per second (m/s) is the SI unit of speed, while the kilometre per hour (kph) is the most widely used unit in daily life.

Learn more about speed here:

https://brainly.com/question/1555553

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