When you redefine the way a standard operator works when it is used with class objects, you have ________ the operator.
(a) reassigned
(b) reformatted
(c) overloaded
(d) overwhelmed
(e) None of these

Respuesta :

Option a is correct. When you redefine the way a standard operator works when it is used with class objects, you have reassigned the operator.

A valid piece of code that resolves to a value is an expression, broadly speaking. Expressions can be divided into two categories: those that solely evaluate and those that have side effects (such assigning values).

An illustration of the first type is the statement x = 7. The variable x is given the value seven in this equation using the = operator. By itself, the phrase evaluates to 7.

An illustration of the second type is the equation 3 + 4. This expression adds the numbers 3 and 4 together using the plus sign (+), yielding the result 7. The result will, however, be immediately discarded if it isn't eventually a part of a larger construct (for instance, a variable declaration like const z = 3 + 4).

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