The speed of a runner increased steadily during the first three seconds of a race. Her speed at half-second intervals is given in the table. Find lower and upper estimates for the distance that she traveled during these three seconds. t (s) 0 0.5 1.0 1.5 2.0 2.5 3.0 v (t/s)|이 6.2 | 10.8 | 14.9 | 18.1 19.4 20.2 Step 1 We will use either Ls or Rs for the upper and lower estimates. Since the runner's speed is an increasing function, then will give the lower estimate, andR will give the upper estimate. ˇ Step 2 The sub-interval widths At for this situation are At- L--JX

Respuesta :

The speed of the runner calculated by the properties of average speed is given by 33.45 feet and the upper limit is 43.45 feet in the last 3 seconds.

The first three seconds of a race saw a runner's speed rapidly grow.

The time is therefore 3 seconds.

The table provides her speed at half-second intervals.

We are aware,

Distance x Time = Speed

Similarly

Distance equals speed x time.

Δt equals 0.5 seconds

Then, the minimum distance travelled overall is equal to

0.5(0 + 6.7 + 9.2 + 14.1 + 17.5 + 19.4).

Terms are multiplied and added.

= 0.5 × 66.9

= 33.45 feet

The maximum distance travelled is equal to

0.5 (6.7 + 9.2 + 14.1 + 17.5 + 19.4 + 20)

= 0.5 × 86.9

= 43.45 feet

As a result, her maximum distance in three seconds is 43.45 feet, and her maximum distance in three seconds is 33.45 feet.

Velocity is the rate at which an item's position changes as perceived from a certain point of view and as measured by a given unit of time (for example, 60 km/h northbound).

Velocity is also the direction at which an object is travelling. Velocity is a fundamental concept in kinematics, the branch of classical mechanics that deals with the motion of bodies.

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