using the solubility rules, predict the identity of the precipitate that forms when aqueous solutions of bacl2 and k2so4 are mixed by writing the balanced chemical equation for the reaction (make sure the states of all reactants and products are shown).

Respuesta :

The precipitate that will be formed at the end of the reaction would be Barium sulphate.

Solubility is the new bond formation between the solute molecules and the solvent molecules. In terms of quantity, solubility is the maximum concentration of solute that dissolves in a known concentration of solvent at any given temperature.

We need to consider each ionic compound (both the reactants and the possible products) in light of the solubility rules. If a compound is soluble, we use the (aq) label with it, indicating that it dissolves. If a compound is not soluble, we use the (s) label with it and assume that it will precipitate out of solution

Barium chloride and potassium sulfate are both ionic compounds. We would expect them to undergo a double displacement reaction with each other.

BaCl2 + K2SO4  BaSO4 + 2 KCl

By examining the solubility rules we see that, while most sulfates are soluble, barium sulfate is not. Because it is insoluble in water we know that it is the precipitate. As all of the other substances are soluble in water we can rewrite the equation.

BaCl2(aq) + K2SO4(aq)  BaSO4(s) + 2 KCl(aq)

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