If n is even number, then 3n must also be even, and vice versa. Since lfn is even, we can find k integers.
in order. for n =2*k. N+1=2*k+1 is then odd.
Since 3k is an integer and 3n+1=6k+1=2"(3k)+1, 3n+1 is odd.
Even 3n =2(3k).
Additionally, we can find an integer p such that n+1-2p+1 such that n = 2p is even if n+1 is odd.
If we can find an integer q such that 3n+1=2g+1 and 3n=2q (since 3 is not divisible by 2), then n is even.
If n is a multiple of 2, then n is an odd number.
In fact, 3n is even equivalent to 3n = 22 when z is an integer, which again indicates that is a
multiple of 2 and then n is even.
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