Question

2d a researcher wanted to know if there was a significant difference in cyber security breaches between cities on two different continents. what test should he conduct to determine if there is a significant difference in cyber security breaches between the continents? write up the results and determine what do the results mean? here is the data set: asia europe 40 25 52 35 63 20 70 18 25 19 19 14 11 9

Answer 1

There is no significant difference between the cyber security breaches of the two destinations and the values are t-value is 0.16221, the p-value is .874721.

We use two sample t-test to check for the significance.

We take the sample of Asia as treatment 1 and that of Europe as treatment 2

Treatment 1

$N_{1}$: 5

$df_{1}$ = N - 1 = 5 - 1 = 4

$M_{1}$: 24.6

$SS_{1}$: 77.2

$S^{2} _{1}$ = $SS_{1}$/(N - 1) = 77.2/(5-1) = 19.3

Treatment 2

$N_{2}$: 6

$df_{2}$ = N - 1 = 6 - 1 = 5

$M_{2}$: 23.5

$SS_{2}$: 1051.5

$S^{2} _{2}$ = $SS_{2}$/(N - 1) = 1051.5/(6-1) = 210.3

T-value Calculation

$S^{2} p_{}$ = ((  df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22) = ((4/9) * 19.3) + ((5/9) * 210.3) = 125.41

s2M1 = s2p/N1 = 125.41/5 = 25.08

s2M2 = s2p/N2 = 125.41/6 = 20.9

t = (M1 - M2)/√(s2M1 + s2M2) = 1.1/√45.98 = 0.16

The t-value is 0.16221. The p-value is .874721. The result is not significant at p < .05

Hence the answer is there is no significant difference between the cyber security breaches of the two destinations and the values are t-value is 0.16221, the p-value is .874721.

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