Given the following balanced reaction of hydrochloric acid and oxygen gas forming chlorine gas and water, how many grams of hydrochloric acid will be needed to form 335 grams of chlorine gas, assuming there is excess oxygen present? (to find the molar mass in the problem, use the periodic table and round the mass to the hundreds place for calculation. ) hcl.

The coefficients in a balanced equation can be used to determine the moles of hydrochloric acid(HCL) to moles of products. Divide the mass by the mass of one mole to get the number of moles.

How to fix?

Cl2 equals 2*35.45, or 70.9 grams.

The amount of moles is 335 70.9.

This equates to 4.72 moles roughly. This value is equal to twice as many moles of hcl.

One mole of mass equals 1 plus 35.46 to 36.45 grams.

Total mass is equal to 2 * (335 70.9) * 36.45.

This weighs about 344.45 grams.

How is 3 percent HCl produced?

Stir 8.26 mL of concentrated HCl into 50 mL of distilled water before adding an additional 100 mL of water. Based on the grams of solute per 100 grams of solution, mass percent solutions are determined.

What are the three methods for determining a solution's concentration?

Concentration (C) is defined as the relationship between the volume of the solution (V) and the mass of the solute (m) that is dissolved in it.

Molality, mole fraction, and molarity are the three methods for calculating the concentration of a solution.

Molarity (M) is determined by the volume of the solution and the number of moles (n) of the solute (V).

The mole fraction (x) is the ratio of the moles of a specific element to the total moles of the substance.

Molality (m) is the ratio of the mass of the solvent to the number of moles (n) of a solute (kg).

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