Answer:
[tex]y=53.75x+70[/tex]
Step-by-step explanation:
From inspection of the given graph with added trendline:
- y-intercept ≈ (0, 70)
- another point on the trendline ≈ (8, 500)
Find the slope of the trendline by substituting the identified points into the slope formula:
[tex]\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{500-70}{8-0}=53.75[/tex]
[tex]\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}[/tex]
Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the trendline:
[tex]\implies y=53.75x+70[/tex]
