during an isothermal compression of an ideal gas, 200 j of heat must be removed from the gas to maintain constant temperature. how much work is done by the gas during the process?

Respuesta :

Work done by the gas during the process is -200J.

Work done can be defined as the product of force and distance travelled by the force.

For an isothermal process, temperature is constant and thus the heat transfer into and out of the system happens slowly so that the system is in thermal equilibrium.

Also, from the first law of thermodynamics, the change in internal energy (ΔU) of a closed system is equal to the sum of the heat transferred (Q) and the work done (W) by the system. i.e

ΔU = W + Q    

The internal energy is dependent on the temperature of the system and since this temperature is constant the change in internal energy is zero (0).

i.e

ΔU = 0

putting the values in the equation of FLOT

⇒ 0 = W + Q

⇒ W = -Q  

Therefore, for such process, the work done is the negative of the heat transferred (heat removed in this case).

Q = 200J

W = -200J

Therefore, the work done is -200 J

The value is negative to show that the process is a compression meaning that work is done by the surrounding on the gas.

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