The ethanol solution (400 ml) was diluted to 4.00 l, which gives a concentration of 0.0400 M. The concentration of the original solution is 0.400 M.
To solve this question, first we need to convert the given volume of a diluted solution in ml
4.00 L×(1000 mL/1 L)=4000 mL
According to the dilution law, degree of dissociation of a weak electrolyte is inversely proportional to the square root of molar concentration. The dilution law in the form of formula is
M₁V₁=M₂V₂
Where, M₁=?
V₁=400 mL
V₂=4000 mL
M₂=0.0400 M
Rearrange the formula for M₁ and solve
M₁=(M₂×V₂/V₁)
M₁=(0.0400 M×4000 mL/400 mL)
M₁=(160 M/400)
M₁=0.400 M
Therefore, the concentration of the original solution is 0.400 M.
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