An aqueous ethanol solution (400 mL) was diluted to 4.00 L, giving a concentration of 0.0400 M. The concentration of the original solution was 0.400 M.
Given:
ethanol solution V₁ = 400 ml
concentration M₂ = 0.0400 M
volume of diluted ethanol V₂ = 4.00 L = 4000 ml
concentration of original solution = M₁ = ?
Formula used:
Dilution is the process of decreasing the concentration of a solute in a solution, usually simply by mixing with more solvent like adding more water to the solution.
in this case, we need to use the dilution formula
M₁V1 = M₂V₂
M₁ = initial molarity
v1 = initial volume in liters
M₂ = final molarity
V₂ = final volume in liters
Solution:
using the dilution formula:
M1 × 400 = 0.04 × 4000
M1 =[tex]\frac{0.04 * 4000 }{400}[/tex]
= 0.400 M
Hence 0.400 M is a correct answer.
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