Question

a 25.0 ml sample of 0.105 m hcl was titrated with 31.5 ml of naoh. what is the concentration of the naoh? group of answer choices 0.075 m 0.105 m 0.132 m 0.0833 m none of the above

Answer 1

A 25.0 ml sample of 0.105 m HCl was titrated with 31.5 ml of NaOH. the concentration of the NaOH is 0.0833 M.

given that :

molarity of HCl, M1 = 0.105 M

volume of HCl V1 = 25 mL

Molarity of NaOH M2 = ?

volume of NaOHV2  = 31.5 mL

by using the titration equation we get :

molarity of HCl × volume of HCl = molarity of NaOH × volume of NaOH

M1 V1 = M2 V2

M2 = (M1 V1 ) / V2

M2 = ( 0.105 × 25 ) / 31.5

M2 = 0.0833 M

The concentration of NaOH = 0.0833 M.

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