a collection of logic gates for which the static power dissipation is zero, and the dynamic power dissipation is 10 mw is operating at 1 ghz with a 1.2-v supply. by what fraction could the power dissipation be reduced if operation at 1.0 v were possible? if the frequency of operation is reduced by the same factor as the supply voltage (i.e., 1.0/1.2), what additional power can be saved?

As a result of primary action, power dissipation is the process by which power is lost as heat. The process of power dissipation happens naturally. The power will be dissipated by each resistor in the circuit that has a voltage drop across it.

Since Pdyn = fc v²oo is proportional to v²oo reducing power supply

from 5v to 3v reduces the power dissipation by a factor of

(3.3)²/5² = 0.436

The power dissipation now become 0.436×10×10⁻³ = 436×10⁻³ = 4.36mw.

Since Pdyn is proportional to reducing f by the some factor as the supply voltage 3.3/5 = 0.66results in reducing the power dissipation

further by factor of 0.66

Additional Saving in power = (1.0.66) X(4.36 × 10⁻³ )

Additional Saving in power = 1.48mw.

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