A beryllium ion with a single electron (denoted $Be^{3+} ) is in an excited state with radius the same as that of the ground state of hydrogen.a. What is n for the Be3+ ion?b. How much energy in eV is needed to ionize the ion from this excited state?

Respuesta :

When conduct electricity an ion from this excited state, 54.4 eV of energy must be provided.

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Briefing:

Since this electron has an energy of,

E₂=-Z²*13.6/n² eV

=-4²*13.6/2² eV

=-54.4eV

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