Question

Exercise 1:

A small puck of mass m=150g is at rest on a horizontal surface. Ignore the frictional forces.

a) Calculate the magnitude of the normal force.

b) At t=0, we apply on the puck a horizontal and constant force F-0. 30 N.

b. 1) Calculate the acceleration of the puck.

b. 2) Calculate the distance covered by the puck then its speed at t₁-0. 50 s.

| Take

Take g-9. 80m/s²

Answer 1

0N is the magnitude of the normal force. 0.002 m/s is the acceleration of the puck when we apply on the puck a horizontal and constant force F-0. 30 N (Newton).

What is the S.I unit of Force?

the S.I unit of force is Newton (N) which is defined as 1N=1Kgm/$s^{2}$.

Data given:

Mass of puck=150g

puck at rest means a (acceleration =0)

Now to find the magnitude of the normal force.

F=ma

F=150*0

F=0N

Hence, 0N is the magnitude of the normal force.

Now, When we apply on the puck a horizontal and constant force F-0. 30 N.

then to find the acceleration of the puck.

a=F/m

a=0.30N/150

a=0.002 m/s

Hence, 0.002 m/s is the acceleration of the puck when we apply on the puck a horizontal and constant force F-0. 30 N.

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