Question

A total of $9000 is invested: part at 6% and the remainder at 10%. How much is invested at each rate if the annual interest is $790?

I know the 6% is 396 I need to know the 10%

Answer 1

6% of a + 10% of (9000 - a) = 790

a = 2750

(9000 - a) = 6250

The amount invested at 6% is 2750.

The amount invested at 10% is 6250.

What is a percentage?

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

Total amount = $9000

Let the part invested for 6% = a

Let the part invested for 10% = (9000 - a)

Now,

6% of a + 10% of (9000 - a) = 790

6% = 6/100 = 0.06

10% = 0.1

0.06a + 0.1(9000 - a) = 790

0.06a + 900 - 0.1a = 790

-0.04a = 790 - 900

0.04a = 110

a = 110/0.04

a = 2750

Now,

9000 - a = 9000 - 2750 = 6250

Thus,

The amount invested at 6% is 2750.

The amount invested at 10% is 6250.

Learn more about percentages here:

https://brainly.com/question/11403063

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