Question

The acceleration of an oscillator undergoing simple harmonic motion is described by the equation a(t)= -(18)cos(30t) , where the time t is measured in seconds. What is the amplitude of this oscillator?

Answer 1

The amplitude of this oscillator is 18 units.

What is the amplitude of a simple harmonic motion?

The amplitude of a simple harmonic motion is the maximum displacement of the wave.

It can also be defined as the maximum vertical height attained by a wave during oscillation.

The general wave equation is given as;

y = A cos(ωt)

where;

• A is the amplitude of the wave

The given wave equation;

a(t) = -18 cos(30t)

From the wave equation given above, the amplitude of the wave corresponds to 18 units.

Thus, we can conclude that the amplitude of the wave can be obtained by comparing the wave equation to general wave equation.

Learn more about amplitude of a wave here: https://brainly.com/question/19036728

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