Question

A right triangle has side lengths 8,15, and 17 as shown below . Use these lengths to find sinL, tanL, and cosL

Answer 1

Answer:

$\sf Sin \ L =\dfrac{8}{17} \\\\\\Tan \ L =\dfrac{8}{15}\\\\\\Cos \ L =\dfrac{15}{17}$

Step-by-step explanation:

Trigonometry ratios:

       $\sf Sin \ L = \dfrac{opposite \ side \ of \angle L}{hypotenuse}$

      $\sf Sin \ L = \dfrac{NM}{LM}=\dfrac{8}{17}$

                $\sf Tan \ L = \dfrac{opposite \ side \ of \ \angle L}{adjacent \ side \ of \ \angle L}$

                $\sf Tan \ L =\dfrac{NM}{LN}=\dfrac{8}{15}$

   $\sf Cos \ L =\dfrac{adjacent \ side \ of \ \angle L}{hypotenuse}$

  $\sf Cos \ L =\dfrac{LN}{LM}=\dfrac{15}{17}$