Answer: Choice D) [tex]y = \frac{1}{5}\text{x}+12\\\\[/tex]
Work Shown:
[tex]-\frac{1}{5}\text{x}+y = 12\\\\y = 12+\frac{1}{5}\text{x}\\\\y = \frac{1}{5}\text{x}+12\\\\[/tex]
It fits the slope-intercept form y = mx+b
Answer:
[tex]\textsf{d.} \quad y=\dfrac{1}{5}x+12[/tex]
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}[/tex]
Given equation:
[tex]-\dfrac{1}{5}x+y=12[/tex]
Rearrange to make y the subject.
Add ¹/₅x to both sides of the equation:
[tex]\implies -\dfrac{1}{5}x+y+\dfrac{1}{5}x=12+\dfrac{1}{5}x[/tex]
[tex]\implies y=12+\dfrac{1}{5}x[/tex]
Rearrange to slope-intercept form:
[tex]\implies y=\dfrac{1}{5}x+12[/tex]
