Question

Use Log(b)2 = 0.401, log(b)3 =0.503, and log(b)5 = 0.842 to approximate the value of the given logarithm to decimal places log(b)50 . Assume that b>0 and $b\neq 1$

Answer 1

Answer:

• ≈ 2.085

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Given

• $log_b2 = 0.401, \ log_b3=0.503, \ log_b5=0.842$

Work out the value of  $log_b50$

• $log_b50=$
• $log_b(2*25)=$
• $log_b(2*5^2)=$
• $log_b2+log_b5^2=$
• $log_b2+2log_b5=$
• $0.401 + 2*(0.842)=$
• $2.085$