Given that 6( y + 3 ) = 2( x + 9 ), find the ratio of x to y.
A. 3/2
B. 3/1
C. 9/2
D. 6/1
![Given that 6 y 3 2 x 9 find the ratio of x to y A 32 B 31 C 92 D 61 class=](https://us-static.z-dn.net/files/d82/a6d8d871aabb6219381cd1b61e72e147.jpg)
![Given that 6 y 3 2 x 9 find the ratio of x to y A 32 B 31 C 92 D 61 class=](https://us-static.z-dn.net/files/d8e/75787bcb18494e36c873b4a4238bb743.png)
Answer:
B. 3/1
Step-by-step explanation:
6(y+3) = 2(x+9)
6y + 18 = 2x + 18
6y - 2x = 18 - 18
6y - 2x = 0
6y = 2x
y/x = 6/2
y/x = 3/1
Answer:
[tex]\textsf{B)} \quad \dfrac{3}{1}[/tex]
Step-by-step explanation:
Given equation:
[tex]6(y+3)=2(x+9)[/tex]
Distribute the parentheses:
[tex]\implies 6y+18=2x+18[/tex]
Subtract 18 from both sides:
[tex]\implies 6y=2x[/tex]
Divide both sides by 2:
[tex]\implies 3y=x[/tex]
Divide both sides by y:
[tex]\implies \dfrac{x}{y}=3[/tex]
Therefore, the ratio of x to y is:
[tex]\implies \dfrac{x}{y}=\dfrac{3}{1}[/tex]