With the diminish within the resistance the bulb's brightness increments. The bulb gets brighter.
Whether a bulb is in series or parallel depends on the voltage and current that flow through it. The total brightness will also depend on the type of bulb used and the light output ratio of the fixture.
Brightness is dependent on bulb power.
and power = [tex]\frac{V^2}{R}[/tex]
The voltage across the bulb lowers when resistance is connected in series, which reduces the brightness of the light.
The current, power, and brightness will all decrease the greater the resistance to current in the wiring, electronics, and bulb.
In contrast, greater brightness results from reduced resistance.
therefore option c. brighter is the correct answer.
To learn more about brightness, refer to:-
https://brainly.com/question/25805832
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