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Note that the total number of kilojoules required to boil 100 Grams of water at 100°C and 1 atmosphere is 2.26kJ.

What is the analysis for the above answer?

The heat of vaporization for water at its boiling point of 100°C is 2260J g-1. This indicates that in order to transform 1 g of water at 100°C to 1 g of steam at 100°C, the water must absorb 2260 J of heat.

Hence, since we are dealing with Kilojoules,

1 Joules = 0.001 Kilojoule; hence,

2260 joules = 2.26kJ

Kilojoules are the units of energy that humans obtain from food and drink (kJ). A calorie is a metric word for energy. Kilojoules and calories are interchangeable terms. A calorie is equal to four kilojoules. Calories may be readily converted to kilojoules and vice versa.

A kiloJoule (kJ) is 1000 Joules, and a megaJoule (MJ) is one million Joules. A related unit is the Watt, which is a power unit. Energy units can be converted to power units by multiplying them by seconds [s], hours [h], or years [yr].

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