Question

When Kayden runs the 400 meter dash, his finishing times are normally distributed

with a mean of 90 seconds and a standard deviation of 1 second. If Kayden were to

run 37 practice trials of the 400meter dash, how many of those trials would be

slower than 88 seconds, to the nearest whole number?





need help ASAP

Answer 1

Given the standard deviation of 1, If Kayden were to run 37 practice trials, of the 400 meters dash, 84%  would be slower than 88 seconds.

What is the computation for the above?

The following information is given:

Kayden runs the 400-meter dash, his finishing times are normally distributed with a mean of 90 seconds and a standard deviation of 1 second;

Mean (μ) = 90

Standard deviation (σ) = 1

We are supposed to find Kayden were to 37 practice trials of the 400-meter dash, how many of those trials would be faster than 88 seconds, to the nearest whole number i.eP (x < 88)

z = (x - μ) /σ

z = 88 - 90/1

z = -2

We must refer to the z table for the value of P; where

p (x < 88) = 0.0228

Recall that Kayden was to run 37 practice trials. hence

P (x < 88) = 37 * 0.0228

= 0.8436

Therefore, to the nearest whole number, we can state that 84% would be faster than 88 seconds.

Learn more about standard deviations:
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