The length and the width of the rectangle is found as 15 and 35 units respectively.
As per the given data-
Let the length be 'x'.
The breadth be 'y'
x/y = 7/3
x = 7y/3
Perimeter = 2(length + breadth)
P = 2( x + y)
P = 2x + 2y
100 = 2(7/3) + 2y
On solving
10y = 150
y = 15 (breadth)
x = 35 (length)
Thus, the length and the width of the rectangle is found as 15 and 35 units respectively.
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